In considering the physical admissibility of the solutions we first noted that if is a finite polynomial that is normalizable because of the extremely rapid fall of the Gaussian factor. We then assumed that if the series for did not terminate, that the resulting would grow so rapidly that even the Gaussian decay of the factor could not make normalizable. In this subsection, we shall investigate why this should be the case.
The key observation which we shall exploit is that for large n the coefficients in the sequence defining behave much like the terms in the expansion for so that, for large X, grows at least like , so that not even multiplication by the Gaussian decay factor will render the wave function normalizable. The basic similarity of the two expansions comes from the behavior of the ratio of the to the terms in the sequence successive terms. For the ratio is
For the ratio approaches the same limit,
We find precisely the same limit in the case of our auxiliary function, . For
the ratio is
Note that the ratio of successive terms may be negative for small values of n so that the terms in the series for the may alternate in sign. Because the ratio approaches a positive limit, However, we are assured that for sufficiently large n, all terms will be of the same sign. Moreover, because , we may find an N so that for all n>N the ratio of successive terms in will exceed where is any number between zero and one. This is important because this is just the quantity (, which is the ratio of successive terms in . If we now multiply by a constant so that the term of is equal in magnitude to the term of , this implies that all successive terms in will exceed their counterparts in . Because all of the terms in question are of the same sign, the absolute value of the sum of all remaining terms in exceeds that of the associated terms in , which is important because we know that g grows too fast to yield a normalizable function. To complete the argument, let be the sum of the first N terms in and be the sum of the first N terms in . Note that both and are finite polynomials. We have just shown that for every there exist a constant and integer N such that for all X,
where is a function which grows at most as quickly as an order polynomial. If we now consider the behavior of the wave function at large values of X, . (The limit of any polynomial times a Gaussian factor is zero.) This statement is true of any . For this to be true for , we see that, as long as the series for does not terminate, we must have as . This completes the proof of our claim that we must reject all solutions of for which the series do not terminate and culminates our power series analysis of the quantum states of the SHO.