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12
This equation comes directly from inserting our result for the
y-component of the tension into the result for the segment response.
To understand it physically, we can rearrange it as
. This states
that the acceleration of each segment is directly proportional to the
tautness of the string
(which makes sense because there should
be more acceleration when there are stronger tension forces), is
inversely proportional to the mass density
of the string (again,
sensible because with more mass density, each segment is heavier and
accelerates less easily) and is directly proportional to the curvature
in the string. The reason why the amount of curvature determines the
acceleration is that if there is no curvature (i.e., the string is
straight), then the y-components of the tension on either end will
be the same and will cancel, leaving no net force. The greater the
curvature, the greater the difference in the y-components on either
end of a segment, and thus the greater the acceleration.
Tomas Arias
Mon Oct 15 16:15:07 EDT 2001