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Strings

We begin by considering the case of the string. All motion is then along the y direction; hence, we need consider only momentum in the y-direction, tex2html_wrap_inline720 . The string is a d=1 dimensional system and we therefore consider the linear momentum density tex2html_wrap_inline724 , the momentum per unit length. Momentum being mass times velocity, the momentum per unit length is the mass per unit length tex2html_wrap_inline726 times the velocity; hence,

  equation96

plays the role of q in (2) when considering conservation of momentumgif.

Next, to understand the flow of momentum, we note that Newton's law for finite systems states

displaymath742

Thus, the rate of change of the total momentum of any system (such as the chunk between points x and tex2html_wrap_inline608 ) is the sum of external forces acting on it. As we have always ignored gravity (and the other long-range forces) in our analyses, the only relevant remaining forces are the contact forces at points x and tex2html_wrap_inline608 .

   figure115
Figure 2: Momentum and energy flow via forces on a string

For the string (Figure 2), the contact force at point x comes from the tension in the segment of the string to the left, tex2html_wrap_inline754 , and the force at point tex2html_wrap_inline608 comes from the tension in the segment to the right tex2html_wrap_inline758 . Consistent with what we already know about lack of x motion in strings, the x components of the tensions cancel, leaving us to consider motion in the y direction only. If we now define the quantity

  equation124

for any point x, we may then write

  equation127

Comparing (6) with (1), we see that the quantity describing the left-right flow F(x) across point x in (1) is nothing other than the y component of the tension force tex2html_wrap_inline774 , with the sign as in (5). Thus, we may interpret force as describing the rate of flow of momentum from one part of a system to another.

We are now ready to consider the continuity equation for momentum along a string. The quantity tex2html_wrap_inline724 from Eq. (4) plays the role of q, the density of the conserved quantity, and the quantity tex2html_wrap_inline774 from Eq. (5) plays the role of F(x), the rate of flow of the conserved quantity. Thus, if indeed momentum is conserved for a string, we expect the following equation to hold,

  equation141

To verify whether this equation holds, we substitute our definitions (4,5) of the density and flow into (7) to find

  equation152

which we know to be true because we recognize it as the wave equation for the string!!!


next up previous contents
Next: Sound Up: Conservation of Momentum Previous: Conservation of Momentum

Tomas Arias
Fri Nov 30 13:33:06 EST 2001